FIT / PHYSICAL CHEMISTRYUniversity, Physical Chemistry
Round 1/6Score 0

Equilibrium Engine

Solve a nonlinear gas equilibrium. Explore reaction quotients, Gibbs energy and temperature dependence.

Equilibrium yieldRun 01

Gas-phase equilibrium vessel

Square particles represent A. Circular particles represent B.

Concept figure: reaction quotient

Q < K Forward reaction Q > K Reverse reaction At equilibrium, Q = K and ΔᵣG = 0.

The system responds until its reaction quotient matches the equilibrium constant.

Set the equilibrium

Species amounts during equilibration

Gibbs energy landscape

Van 't Hoff relationship

The chemistry

Model reaction: A(g) ⇌ 2B(g). Standard pressure p° = 1 bar. All gases behave ideally.

Amounts at extent ξ: nA = nA,0 − ξ; nB = nB,0 + 2ξ. Units: mol.

Pressure quotient: Qp = (pB/p°)² / (pA/p°), where pi = yiP.

Standard Gibbs energy: ΔᵣG° = ΔᵣH° − TΔᵣS° = −RT ln Kp.

Van 't Hoff: ln Kp = −ΔᵣH°/(RT) + ΔᵣS°/R. The gradient of ln K against 1/T is −ΔᵣH°/R.

Reaction direction: ΔᵣG = RT ln(Qp/Kp). Forward if Q < K, reverse if Q > K.

Equilibrium calculation: numerically solve Qp(ξ) = Kp for an admissible ξ. A minimum of G(ξ) occurs at equilibrium.

Assumptions: ideal gases, fixed total pressure and temperature within each equilibrium calculation, constant ΔᵣH° and ΔᵣS°, no inert gas or side reactions. Kp and Qp are dimensionless.

R = 8.31 J mol⁻¹ K⁻¹. Temperature is in K, pressure in bar, and Gibbs energy in kJ.